Answer
$|A|=5$, $T=\frac{\pi}{2}$, $\text{phase shift}=\frac{\pi}{4}$.
Work Step by Step
The general form for the cosinusoidal function is: $y=A\cos{(\omega x-\phi)}+B$ where $|A|$ is the amplitude, $B$ is the vertical shift, the period can be computed by the formula $T=\frac{2\pi}{\omega}.$
The phase shift is $\frac{\phi}{\omega}$, hence $\phi=\omega\cdot\text{phase shift}.$
Hence here: $|A|=|5|=5$, $B=0$, $\omega=4$, thus $T=\frac{2\pi}{\omega}=\frac{2\pi}{4}=\frac{\pi}{2}$, $\phi=\pi$, hence $\text{phase shift}=\frac{\phi}{\omega}=\frac{\pi}{4}$.
