Answer
$\frac{9\pi}{2}\approx14.14\ cm^2$
Work Step by Step
Given $r=6cm, \theta=45^\circ=\frac{\pi}{4}$, we have the area $A=\frac{1}{2}r^2\theta=\frac{1}{2}(6)^2(\frac{\pi}{4})=\frac{9\pi}{2}\approx14.14\ cm^2$
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