Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 475: 10

Answer

b

Work Step by Step

$\frac{1}{1-sin(\theta)}+\frac{1}{1+sin(\theta)}=\frac{(1+sin(\theta))+(1-sin(\theta))}{(1+sin(\theta)(1-sin(\theta)}=\frac{2}{1-sin^2(\theta)}$. The identity says: $sin^2(\theta)+cos^2(\theta)=1$. Hence $\frac{2}{1-sin^2(\theta)}=\frac{2}{cos^2(\theta)}=2sec^2(\theta)$. Hence the answer is b.
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