Answer
$\frac{5\pi}{2}\approx7.85\ in$
Work Step by Step
Given $r=6\ in$ and a central angle of $75^\circ \longrightarrow \theta=\frac{5\pi}{12}$, we have the arc length as $s=r\theta=6(\frac{5\pi}{12})=\frac{5\pi}{2}\approx7.85\ in$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 459: 90
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