Answer
$x=\sec(y)$, $\geq1$, $0$, $\pi$.
Work Step by Step
If $\sec{(x)}=y$ then for the inverse function $\sec^{-1}{(y)}=x.$ Hence here it means $x=\sec(y)$, where $|x|\geq1$ and $0\leq y\leq \pi$.
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