## Precalculus (10th Edition)

a)$32.34^\circ$. b)$63^\circ10'48''$.
We know that $1^\circ=60'$ and that $1'=60''$. Using these we do the conversions: a) $32^\circ20'35''=32^\circ+\frac{20}{60}^\circ+\frac{35}{60\cdot60}^\circ\approx32.34^\circ$. b) $63.18^\circ=63^\circ+0.18\cdot60'\\=63^\circ+10.8'\\=63^\circ+10'+0.8\cdot60''=63^\circ+10'+48''$.