Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 435: 48


a)$32.34^\circ$. b)$63^\circ10'48''$.

Work Step by Step

We know that $1^\circ=60'$ and that $1'=60''$. Using these we do the conversions: a) $32^\circ20'35''=32^\circ+\frac{20}{60}^\circ+\frac{35}{60\cdot60}^\circ\approx32.34^\circ$. b) $63.18^\circ=63^\circ+0.18\cdot60'\\=63^\circ+10.8'\\=63^\circ+10'+0.8\cdot60''=63^\circ+10'+48''$.
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