Answer
$-2cos(x)$
$cos(-2x)$
See graph.
Work Step by Step
Step 1. Given $f(x)=-2x, g(x)=cos(x)$, we have $(f\circ g)(x)=f(g(x))=-2cos(x)$
Step 2. We have $(g\circ f)(x)=g(f(x))=cos(-2x)$
Step 3. See graph.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.4 Graphs of the Sine and Cosine Functions - 6.4 Assess Your Understanding - Page 410: 81
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