Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 396: 131

Answer

$(\sin\theta \cos\phi)^2+(\sin\theta \sin\phi)^2+(\cos\theta)^2=\sin\theta^2\cos\phi^2+\sin\theta^2\sin\phi^2+(\cos\theta)^2=(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2$ I know that $\cos\phi^2+\sin\phi^2=1$, hence: $(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2=(\sin\theta)^2\cdot1+(\cos\theta)^2=(\sin\theta)^2+(\cos\theta)^2=1.$

Work Step by Step

$(\sin\theta \cos\phi)^2+(\sin\theta \sin\phi)^2+(\cos\theta)^2=\sin\theta^2\cos\phi^2+\sin\theta^2\sin\phi^2+(\cos\theta)^2=(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2$ I know that $\cos\phi^2+\sin\phi^2=1$, hence: $(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2=(\sin\theta)^2\cdot1+(\cos\theta)^2=(\sin\theta)^2+(\cos\theta)^2=1.$
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