Answer
$(\sin\theta \cos\phi)^2+(\sin\theta \sin\phi)^2+(\cos\theta)^2=\sin\theta^2\cos\phi^2+\sin\theta^2\sin\phi^2+(\cos\theta)^2=(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2$
I know that $\cos\phi^2+\sin\phi^2=1$, hence:
$(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2=(\sin\theta)^2\cdot1+(\cos\theta)^2=(\sin\theta)^2+(\cos\theta)^2=1.$
Work Step by Step
$(\sin\theta \cos\phi)^2+(\sin\theta \sin\phi)^2+(\cos\theta)^2=\sin\theta^2\cos\phi^2+\sin\theta^2\sin\phi^2+(\cos\theta)^2=(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2$
I know that $\cos\phi^2+\sin\phi^2=1$, hence:
$(\sin\theta)^2(\cos\phi^2+\sin\phi^2)+(\cos\theta)^2=(\sin\theta)^2\cdot1+(\cos\theta)^2=(\sin\theta)^2+(\cos\theta)^2=1.$