Answer
$R=1988.32$ meters.
$H=286.99$ meters.
Work Step by Step
$R=\frac{v_0^2\sin{(2\theta)}}{g}=\frac{150^2\sin{(2\cdot\frac{\pi}{6})}}{9.8}=\frac{150^2\cdot\frac{\sqrt3}{2}}{9.8}\approx1988.32$ meters.
$H=\frac{v_0^2\sin^2{(\theta)}}{2g}=\frac{150^2\sin^2{(\frac{\pi}{6})}}{9.8}=\frac{150^2\cdot(\frac{1}{2})^2}{9.8}\approx286.99$ meters.
