Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Cumulative Review - Page 349: 9


$f(g(x))=(\frac{2}{x-3})^2+2$. The domain is all real numbers except $-3$. $f(g(5))=3$.

Work Step by Step

$f(g(x))=f(\frac{2}{x-3})=(\frac{2}{x-3})^2+2$. The denominator of a function cannot be $0$, hence the domain is all real numbers except $-3$. $f(g(5))=(\frac{2}{5-3})^2+2=(\frac{2}{2})^2+2=1^2+2=3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.