## Precalculus (10th Edition)

$x=-26$
Distribute $3$ on th eleft side and $4$ on the right side of the equation to obtain: $3(x-2)=4(x+5)\\ 3x-6=4x+20$ Subtract $20$ from each side: $3x-6-20=4x+20-20\\ 3x-26=4x$ Subtract $3x$ from each side: $3x-26-3x=4x-3x\\ -26=x$