Answer
$6$
Work Step by Step
$log_2(x+3)=2log_2(x-3)\longrightarrow log_2(x+3)=log_2(x-3)^2\longrightarrow x+3=(x-3)^2\longrightarrow x^2-7x+6=0\longrightarrow (x-1)(x-6)=0\longrightarrow x=1,6$. Check, only $x=6$ is the answer.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.7 Financial Models - 5.7 Assess Your Understanding - Page 323: 79
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