Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.4 Logarithmic Functions - 5.4 Assess Your Understanding - Page 298: 134

Answer

$6.9.$ magnitude

Work Step by Step

$M(x)=log{\frac{x}{x_0}}$. $x=7943$, $x_0=10^-3$, hence after plugging these values in: $M(x)=log{\frac{7943}{10^-3}}\approx6.9.$
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