Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 269: 109

zeros $ \frac{-5\pm\sqrt {13}}{6}$ x-intercepts $ \frac{-5\pm\sqrt {13}}{6}$

Step 1. Using the quadratic formula, we have zeros $x=\frac{-5\pm\sqrt {5^2-4(3)}}{2(3)}=\frac{-5\pm\sqrt {13}}{6}$ Step 2. The x-intercepts are the same as the zeros, $x= \frac{-5\pm\sqrt {13}}{6}$