Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 268: 89

Answer

Domain: $[0,\infty)$, inverse:$f^{-1}(x)=x$.

Work Step by Step

According to the horizontal line test, we restrict the domain to $[0,\infty)$, (such that for every $y=f(x)$, there is a unique $x$, because we can only find the inverse of a one-to-one function) then $f^{-1}(x)$=x.$
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