Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 266: 38

Answer

$f(g(x))=f(\frac{x}{2}-3)=2(\frac{x}{2}-3)+6=x-6+6=x$ $g(f(x))=g(2x+6)=\frac{2x+6}{2}-3=x+3-3=x$ There are no values to be excluded.

Work Step by Step

$f(g(x))=f(\frac{x}{2}-3)=2(\frac{x}{2}-3)+6=x-6+6=x$ $g(f(x))=g(2x+6)=\frac{2x+6}{2}-3=x+3-3=x$ There are no values to be excluded.
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