## Precalculus (10th Edition)

Published by Pearson

# Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 254: 14

#### Answer

a) 95; b) 127; c) 17; d) 1.

#### Work Step by Step

We are given the functions: $f(x)=3x+2$ $g(x)=2x^2-1$ a) $(f\circ g)(4)=f(g(4))=f(2(4^2)-1)=f(31)=3(31)+2=95$ b) $(g\circ f)(2)=g(f(2))=g(3(2)+2)=g(8)=2(8^2)-1=127$ c) $(f\circ f)(1)=f(f(1))=f(3(1)+2)=f(5)=3(5)+2=17$ d) $(g\circ g)(0)=g(g(0))=g(2(0^2)-1)=g(-1)=2((-1)^2)-1=1$

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