Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 4 - Polynomial and Rational Functions - 4.4 Polynomial and Rational Inequalities - 4.4 Assess Your Understanding - Page 220: 68


$0\cup [3,\infty)$

Work Step by Step

The equation according to the text: $x^3-3x^2\geq0\\x^2(x-3)\geq0$ The zeros: $x=0$ or $x-3=0\\x=3$. Then, according to the table (where I used the zeros ($x=0,3$) to divide the number line into different parts), the solution set: $0\cup [3,\infty)$ because the function is non-negative in this interval.
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