Answer
$(-\infty,-3]U[-2,-1]$
Work Step by Step
Step 1.Identify boundary points (zeros) as $x=-3,-2,-1$ which divide the x-axis into four intervals $(-\infty,-3],[-3,-2],[-2,-1],[-1,\infty)$
Step 2. Choose test values in each interval $x=-4,-2.5,-1.5,0$ and test the inequality to get $True,\ False,\ True, \ False$
Step 3. Thus the solution intervals are $(-\infty,-3]U[-2,-1]$
