Chapter 4 - Polynomial and Rational Functions - 4.2 Properties of Rational Functions - 4.2 Assess Your Understanding - Page 199: 70

$(-3,11)$ and $(2,-4)$

Step 1. To find the intersects, let $f(x)=g(x)$, we have $-3x+2=x^2-2x-4$ or $x^2+x-6=0$ Step 2. Factor and solve the equation $(x+3)(x-2)=0$, thus $x=-3$ or $x=2$ Step 3. For $x=-3$, we have $y=f(-3)=-3(-3)+2=11$, thus we have point $(-3,11)$ Step 4. For $x=2$, we have $y=f(2)=-3(2)+2=-4$, thus we have point $(2,-4)$