Answer
$x= \frac{-2\pm\sqrt 7}{2}$
Work Step by Step
To find the x-intercept of $f(x)=4x^2+8x-3$, let $f(x)=0$, we have $4x^2+8x-3=0$, thus $x=\frac{-8\pm\sqrt {8^2+4(4)(3)}}{2(4)}=\frac{-2\pm\sqrt 7}{2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 4 - Polynomial and Rational Functions - 4.1 Polynomial Functions and Models - 4.1 Assess Your Understanding - Page 188: 136
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