Answer
$x=2$
Please see the step-by-step part for the explanation.
Work Step by Step
Since the square of a real number can only be non-negative, the only number that is not a solution is when $(x-2)^2=0$.
Solve the equation to obtain:
\begin{align*}
(x-2)^2&=0\\
\sqrt{(x-2)^2}&=\pm\sqrt{0}\\
x-2&=0\\
x&=2
\end{align*}
Thus, the only number that is not a solution of the given inequality is $x=2$.
