Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - 3.4 Build Quadratic Models from Verbal Descriptions and from Data - 3.4 Assess Your Understanding - Page 155: 24

Answer

$\frac{22}{3}$

Work Step by Step

Step 1. Identify the given quantities, we have $a=-1, c=4, h=1$ Step 2. Use the formula, we have $Area=\frac{h}{3}(2ah^2+6c)=\frac{1}{3}(2(-1)(1)^2+6(4))=\frac{22}{3}$
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