Answer
center $(5,-2)$, $r=3$.
Work Step by Step
Step 1. Form squares of the equation to get $(x-5)^2+(y+2)^2=-20+25+4=9$
Step 2. We can identify the center as $(5,-2)$ and radius as $r=3$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 3 - Linear and Quadratic Functions - 3.3 Quadratic Functions and Their Properties - 3.3 Assess Your Understanding - Page 148: 103
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