Answer
See graph and explanations.
Work Step by Step
Step 1. See graph for $f(x)=x^2+bx+1$ for $b=-4,0,4$
Step 2. As $f(x)=x^2+bx+1=(x+\frac{b}{2})^2+1-(\frac{b}{2})^2$, we can see that different $b$ values cause different vertex positions.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 3 - Linear and Quadratic Functions - 3.3 Quadratic Functions and Their Properties - 3.3 Assess Your Understanding - Page 147: 96
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