Answer
$(g-f)(x)=x^2-8x+12$
Work Step by Step
Given $f(x)=5x-8$ and $g(x)=x^2-3x+4$, we have:
$\begin{align*}
(g-f)(x)&=g(x)-f(x)\\
&=x^2-3x+4-(5x-8)\\
&=x^2-3x+4-5x+8\\
&=x^2-8x+12
\end{align*}$
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