Answer
Refer to the graph below.
$x$-intercept: $1$
no $y$-intercept.
domain $[1,\infty)$
range $[0,\infty)$
Work Step by Step
Step $1$. Graph $y=\sqrt{x}$. Refer to the purple curve below.
To obtain $h(x)=\sqrt {x-1}$, shift the curve of the graph of $y=\sqrt x$ one unit to the right (refer to the red graph)..
Step $2$. We can identify the $x$-intercept to be $1$. The graph has no $y$-intercept.
Step $3$. The graph shows that the value of $x$ is any real number from $1$ to the right so the domain is $[1,\infty)$.
The graph shows that the value of $y$ is any real number from $0$ and above so the range is $[0,\infty)$..
