Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - Chapter Review - Cumulative Review - Page 117: 5


$x=\dfrac{-7}{2}$ or $x=\dfrac{1}{2}$

Work Step by Step

RECALL: $|x|=a \longrightarrow x=a \text{ or } x =-a$ use the definition above to obtain $|2x+3|=4\longrightarrow 2x+3=4 \text{ or } 2x+3=-4$ Solve each equation to obtain: \begin{align*} 2x&=4-3 &\text{or}& &2x=-4-3\\ 2x&=1 &\text{or}& & 2x=-7\\ x&=\frac{1}{2} &\text{or}& &x=-\frac{7}{2} \end{align*}
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