Answer
$(-\infty,0)$
Work Step by Step
When $x\lt0$, function $f(x)=x^2$ is decreasing, thus the interval is $(-\infty,0)$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 2 - Functions and Their Graphs - 2.4 Library of Functions; Piecewise-defined Functions - 2.4 Assess Your Understanding - Page 90: 4
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