## Precalculus (10th Edition)

$y+2=5(x-3)$
We know that if the slope of a line is $m$ and it contains $P_1(x_1,y_1)$, then the point-slope form of the line's equation is: $y-y_1=m(x-x_1)$ Hence, the point-slope form of the equation of the given line: $y-(-2)=5(x-3)\\ y+2=5(x-3)$