## Precalculus (10th Edition)

$y=\frac{2}{3}x+8$
We know that if the slope of a line is $m$ and it contains $P_1(x_1,y_1)$, then its equation is: $y-y_1=m(x-x_1).$ Hence here: $y-4=\frac{2}{3}[x-(-6)]\\ y-4=\frac{2}{3}(x+6)\\ y-4=\frac{2}{3}x+4\\y=\frac{2}{3}x+8$