Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 59: 115



Work Step by Step

We need for the functions to be equal that also their domains are equal (and other things too). $f(x)$ has $-1$ in its domain but $g(x)$ is undefined for $-1$ (although $g(x)=\frac{x^2-1}{x+1}=\frac{(x-1)(x+1)}{x+1}=x-1$), hence it is not in its domain, thus their domains are not the same, therefore the functions are not equal.
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