Answer
$7$
Work Step by Step
Factor each polynomial:
$$f'(1)\\=\lim_{x\to 1}\frac{f(x)-f(1)}{x-1}\\=\lim_{x\to 1}\frac{2x^2+3x+2-(2(1)^2+3(1)+2)}{x-1}\\=\lim_{x\to 1}\frac{2x^2+3x-5}{x-1}\\=\lim_{x\to 1}\frac{(x-1)(2x+5)}{x-1}.$$
Cancel the common factors: $$\lim_{x\to 1}2x+5\\=2(1)+5=7$$