Answer
$\int_{1}^{4}(-x^2+5x+3)dx$
Work Step by Step
If $f(x)\geq0$ on an interval $[a,b]$ then the are under the graph of $f(x)$ is represented by $\int_{a}^{b}f(x)dx$, thus here the area: $\int_{1}^{4}(-x^2+5x+3)dx$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Chapter Test - Page 909: 16
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