Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.4 The Tangent Problem; The Derivative - 14.4 Assess Your Understanding - Page 899: 54

Answer

$23.66.$

Work Step by Step

By Heron's theorem $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence here $s=\frac{6+9+13}{2}=14$, $K=\sqrt{14(14-6)(14-9)(14-13)}\approx23.66.$
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