Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.2 Algebra Techniques for Finding Limits - 14.2 Assess Your Understanding: 30

Answer

$\dfrac {1}{2}$

Work Step by Step

Factor each polynomial: $\lim _{x\rightarrow -1}\dfrac {x^{2}+x}{x^{2}-1} \\=\lim _{x\rightarrow -1}\dfrac {x\left( x+1\right) }{\left( x-1\right) \left( x+1\right) }$ Cancel the common factors: $=\lim _{x\rightarrow -1}\dfrac {x}{x-1} \\=\dfrac {-1}{-1-1} \\=\dfrac {-1}{-2} \\=\dfrac {1}{2} \\=0.5$
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