Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.1 Finding Limits Using Tables and Graphs - 14.1 Assess Your Understanding - Page 876: 1


See graph

Work Step by Step

We are given the function: $f(x)=\begin{cases} 3x-2,\text{ if }x\not=2\\ 3,\text{ if }x=2 \end{cases}$ In order to draw the line $y=3x-2$ we use its intercepts: $x=0\Rightarrow y=3(0)-2=-2$ $y=0\Rightarrow 0=3x-2\Rightarrow x=\dfrac{2}{3}$ The point $(2,3(2)-2)=(2,4)$ doesn't belong to the graph of $y=3x-2$. The value corresponding to $x=2$ is $y=3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.