## Precalculus (10th Edition)

We are given the function: $f(x)=\begin{cases} 3x-2,\text{ if }x\not=2\\ 3,\text{ if }x=2 \end{cases}$ In order to draw the line $y=3x-2$ we use its intercepts: $x=0\Rightarrow y=3(0)-2=-2$ $y=0\Rightarrow 0=3x-2\Rightarrow x=\dfrac{2}{3}$ The point $(2,3(2)-2)=(2,4)$ doesn't belong to the graph of $y=3x-2$. The value corresponding to $x=2$ is $y=3$.