Answer
$56$
Work Step by Step
We know that $C(n,r)=\frac{n(n-1)(n-2)...(n-k+1)}{r!}$. Also $C(n,0)=1$ by convention. Also $C(n,r)=C(n,n-r).$
Hence $C(8,3)=\frac{8\cdot7\cdot6}{3!}=56$.
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