Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 857: 70

Answer

$80$

Work Step by Step

We know that in a geometric sequence, if $a_1$ is the first term and $r$ is the common ratio, then the $n^{th}$ term is given by he fomumla $a_n=a_1\cdot r^{n-1}.$ Hence, here $a_n=5\cdot (-2)^{n-1}$ Thus, $a_{5}=5\cdot (-2)^{5-1}=80$
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