Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.1 Counting - 13.1 Asses Your Understanding - Page 847: 7

Answer

$n(A)+n(B)-n(A\cap B)$

Work Step by Step

It is the number of elements in A plus the number of elements in B, minus the number of elements in their intersection (because we counted those twice). Thus, $n(A\cup B)=n(A)+n(B)-n(A\cap B)$
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