Answer
$\dfrac{8}{17}i-\dfrac{15}{17}j$
Work Step by Step
If $v=ai+bj$, then the unit vector $u$ in the direction of $v$ is $u=\dfrac{v}{||v||}$, where $||v||=\sqrt{a^2+b^2}.$
Note that here,
$||v||=\sqrt{8^2+(-15)^2}=\sqrt{289}=17$
Hence
$u=\dfrac{8i-15j}{17}\\
u=\dfrac{8}{17}i-\dfrac{15}{17}j$