Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 808: 74

Answer

$871$

Work Step by Step

I know that $\sum_{k=1}^{n} (k)=\frac{n(n+1)}{2}.$ Hence $\sum_{k=1}^{26} (3k-7)=\sum_{k=1}^{26} (3k)+\sum_{k=1}^{26} (-7)=3\sum_{k=1}^{26} (k)+26(-7)=3\frac{26(26+1)}{2}-182=3(351)-182=871$
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