Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.6 Polar Equations of Conics - 10.6 Assess Your Understanding - Page 685: 25



Work Step by Step

After multiplying with the denominator of the fraction: $r(1+\cos{\theta})=1\\r+r\cos{\theta}=1\\r=1-r\cos{\theta}\\r^2=(1-r\cos{\theta})^2$. We know that $r^2=x^2+y^2$ and that $x=r\cos\theta,y=r\sin\theta$. Hence $r^2=(1-r\cos{\theta})^2$ becomes: $x^2+y^2=(1-x)^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.