Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - 10.3 The Ellipse - 10.3 Assess Your Understanding - Page 657: 39

Answer

$\frac{(x+1)^2}{4}+(y-1)^2=1$

Work Step by Step

The ellipse has a major axis parallel to the x-axis, hence the equation of the ellipse here has the form $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$, where $a\gt b\gt0$ and $(h,k)$ is the center. $(h,k)=(-1,1)$, $a=2$, $b=1$, hence the equation is: $\frac{(x-(-1))^2}{2^2}+\frac{(y-1)^2}{1^2}=1\\\frac{(x+1)^2}{4}+(y-1)^2=1$
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