## Precalculus (10th Edition)

$\frac{(x+1)^2}{4}+(y-1)^2=1$
The ellipse has a major axis parallel to the x-axis, hence the equation of the ellipse here has the form $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$, where $a\gt b\gt0$ and $(h,k)$ is the center. $(h,k)=(-1,1)$, $a=2$, $b=1$, hence the equation is: $\frac{(x-(-1))^2}{2^2}+\frac{(y-1)^2}{1^2}=1\\\frac{(x+1)^2}{4}+(y-1)^2=1$