Answer
The slope of the line $4x-5y=-20$ is $\frac{4}{5}$.
The $y-$ intercept of the line $4x-5y=-20$ is $(0,\,4)$.
The graph of line is as shown below:
Work Step by Step
Convert to slope intercept form:
$4x-5y=-20$
Subtract $4x$ on both sides,
$-5y=-20-4x$
Multiply on both sides by $-1$,
$5y=20+4x$
Divide on both sides by $5$,
$y=\frac{20+4x}{5}$
$\Rightarrow y=\frac{20}{5}+\frac{4}{5}x$
$\Rightarrow y=\frac{4}{5}x+4$
By comparing $y=\frac{4}{5}x+4$ with the point-slope form $y=mx+c$,
the coefficient of $x$ is $\frac{4}{5}$, and the constant is $4$.
Therefore, the slope is $\frac{4}{5}$, and the $y-$ intercept is $4$.
The $y-$ intercept is $4$. That means the point $\left( 0,4 \right)$ is on the line.
The slope of the line is $\frac{4}{5}$. Move from $(0,4)$ 4 units up and 5 units right. Connect the points with a line.
