Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - Chapter Review - Chapter Test - Page 42: 5

Answer

The graph is shown below

Work Step by Step

The graph of ${{y}^{2}}=x$ consists of points $\left( x,y \right)$. To graph the equation ${{y}^{2}}=x$, plot some points $\left( x,\,y \right)$ and join them. To find some points $\left( x,\,y \right)$, choose random $y$ values and find the corresponding $x$ values by using the equation${{y}^{2}}=x$. ${{y}^{2}}=x$ can be written as $x={{y}^{2}}$. So, use $x={{y}^{2}}$ to find the $\left( x,y \right)$ values. If $y=0$, then $x={{\left( 0 \right)}^{2}}=0$. Therefore, the point $\left( 0,0 \right) $ is on the graph. If $y=1$, then $x={{\left( 1 \right)}^{2}}=1$. Therefore, the point $\left( 1,1 \right)$ is on the graph. If $y=-1$, then $x={{\left( -1 \right)}^{2}}=1$. Therefore, the point $\left( 1,-1 \right)$ is on the graph. If $y=2$, then $x={{\left( 2 \right)}^{2}}=4$. Therefore, the point $\left( 4,2 \right)$ is on the graph. If $y=-2$, then $x={{\left( -2 \right)}^{2}}=4$. Therefore, the point $\left( 4,-2 \right)$ is on the graph. If $y=3$, then $x={{\left( 3 \right)}^{2}}=9$. Therefore, the point $\left( 9,3 \right)$ is on the graph. If $y=-3$, then $x={{\left( -3 \right)}^{2}}=9$. Therefore, the point $\left( 9,-3 \right)$ is on the graph. If $y=-5$, then $x={{\left( -5 \right)}^{2}}=25$. Therefore, the point $\left( 25,5 \right)$ is on the graph. If $y=5$, then $x={{\left( -5 \right)}^{2}}=25$. Therefore, the point $\left( 25,-5 \right)$ is on the graph. Draw the graph by plotting these points and connecting them. The graph of the equation ${{y}^{2}}=x$ represents the equation of a parabola.
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