Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.1 The Distance and Midpoint Formulas - 1.1 Assess Your Understanding - Page 8: 64


$60\sqrt2\text{ ft}$

Work Step by Step

The triangle that the diagonal makes with two sides of the square is a right triangle. Using the Pythagorean Theorem, the diagonal length is: $= \sqrt{60^2+60^2}\\ =\sqrt{2(60^2)}\\ =60\sqrt2\text{ ft}$
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