## Precalculus (10th Edition)

We know that for a rectangle to result in a square screen, $\frac{X_{max}-X_{min}}{Y_{max}-Y_{min}}=\frac{3}{2}$ must be true. Here: $\frac{X_{max}-X_{min}}{Y_{max}-Y_{min}}=\frac{6-(-6)}{2-(-2)}=\frac{12}{4}=\frac{3}{1}\ne\frac{3}{2}$. Thus it is not a square screen.