Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A50: 2

Answer

$(2x-3)(x+1)$

Work Step by Step

The given expression $2x^2-x-3$ has $a=2, b=-1$, and $c=-3$. Thus, $ac=2(-3)=-6$. Look for factors of $-6$ whose sum is $b=-1$. The factors are $-3$ and $2$. Rewriting $-x$ using the factors found yields $-3x+1x$. Thus, the given polynomial is equivalent to $2x^2-3x+x-3$ Group the first two terms together and group the last two terms together to obtain: $(2x^2-3x)+(2x-3)$ Factor out the greateset common factor (GCF) in each group. $=x(2x-3)+1(2x-3)$ Factor out $(2x-3)$. $=(2x-3)(x+1)$
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