Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 7 - Trigonometry and Periodic Functions - Review Exercises and Problems for Chapter Seven - Page 316: 25

Answer

$\frac{11\pi}{6}$ rad.

Work Step by Step

Using the fact that $\pi \: \textrm{rad.} = 180^\circ$, $$330^\circ \cdot \frac{\pi \: \textrm{rad.}}{180^\circ}=\frac{33\pi}{18}=\frac{11\pi}{6}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.